SOLVED: Consider the following reaction: 4Fe (s) + 3O2 (g) —> 2Fe2O3 (s) If 5.0 moles of Fe and 4.0 moles of O2 are the present as the reactants, determine the limiting
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SOLVED: 4Fe + 3O2 2Fe2O3 If 44.2 grams of oxygen react with an excess of iron, what mass of Fe2O3 can form? (Fe2O3= 159.70 g/mol) a. 147 g b. 331 g c. 294 g d. 221 g
SOLVED: 4Fe(s)+3O2(g)⟶2Fe2O3(s) If 71.3 g of Fe and 65.0 g of O2 are mixed, and 85.0 g of Fe2O3 is actually obtained, what is the percent yield of Fe2O3 for the reaction?
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2Fe + 3O2 → 2Fe2O3
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